Răspuns:
[tex]\displaystyle\bf\ 2^{2*2+3x-2} =8\\\\2^{4+3x-2} =2^{3} \\\\2^{2+3x} =2^{3}\\\\ avem \:\:\:aceeasi\:\:\:baza\:\:2\\\\2+3x=3\\\\3x=3-2\\\\3x=1\\\\x=1:3\\\\ \displaystyle\bf\boxed{x=\frac{1}{3}}[/tex]
