Salut.
[tex]\displaystyle{\sqrt{x^{2}}^{2}-9=(x-3)^{2} }[/tex]
[tex]\displaystyle{x}[/tex]² - 9 = [tex]\displaystyle{x}[/tex]² - 6[tex]\displaystyle{x}[/tex] + 9
-9 = -6[tex]\displaystyle{x}[/tex] + 9
6[tex]\displaystyle{x}[/tex] = 9 + 9
6[tex]\displaystyle{x}[/tex] = 18
[tex]\displaystyle{x}[/tex] = 18 ÷ 6
[tex]\boxed{x=3}[/tex]
- Lumberjack25
