Explicație pas cu pas:
Bc ipotenuza, m (<A)=90, m (<C 30)=> ( teorema <30grade: AB= 1/2 x BC
AB=1/2x 20
AB=10
m(<a)=90=> ( T.P)
[tex]bc {}^{2} = ab {}^{2} + ac {}^{2} [/tex]
[tex]20 {}^{2} = 10 {}^{2} + ac {}^{2} [/tex]
[tex]400 = 100 + ac { }^{2} \\ ac {}^{2} = 300 \\ ac = 10 \sqrt{3} cm[/tex]
AD perpendiculara pe ipotenuza BC=>
[tex]ad = \frac{ab \times ac}{bc } \\ \\ ad = \frac{10 \times 10 \sqrt{3} }{20} \\ ad = 5 \sqrt{3} [/tex]
