Răspuns:
c,m= niu/V---> niu= 0,1mol/lx0.2 l= 0,02mol CH3COOH
2CH3COOH+ CaCO3---< > (CH3COO)2Ca+ H2O+ CO2
2mol..................1mol
0.02mol..........x= niu=0,01mol CaCO3 PUR
m=niuxM=0,01molx100g/mol= 1g CaCO3 PUR
p=m,px100/m,i--> m,i= 1x100/80g=1,25g calcar
Explicație: