Răspuns:
[tex]\sqrt{2x+3} = x+1\\ \\(\sqrt{2x+3})^{2} = (x+1)^{2} \\\\2x+3 = x^{2} +2x+1\\\\3 = x^{2} +1\\\\x^{2} =2\\\\x =\sqrt{2}[/tex]
Răspuns:
ridicam la patrat ambii membrii
=> 2x+3=(x+1)²=> 2x+3=x²+2x+1 =>x²-2=0 => x² = 2=> x= rad(2) si -rad (2)
