Răspuns :
CB-ipotenuza
Teorema lui Pitagora:ipotenuza^2=o cateta ^2+cealalta cateta^2
CB^2=AC^2+AB^2
CB^2=12^2+16^2
CB^2=144+256
CB^2=400
CB=radical din 400
CB=20 cm
T. P.
ip^2=c1^2+c2^2
In trABC, A=90°=>conform T. P. BC^2=AB^2+AC^2=>BC^2=16^2+12^2=256+144=400
BC^2=radical din 400=>BC=20