ms = 200 g , c% = 60%
c% = mdx100/ms
=> md = mdxc%/100
= 200x60/100 = 120 g CH3COOH
120 g m g
2CH3COOH + Mg --> (CH3COO)2Mg + H2
2x60 142
=> m = 120x142/2x60 = 142 g (CH3COO)2Mg obtinuta la 100% (teoretic) ... dar la 80% cat s-ar fi obtinut practic...??
100% ....................... 142 g
80% ............................ z = 113,6 g acetat de Mg