Răspuns:
Explicație:
2.
n = m : M
126 g HNO3
MHNO3= 1 + 14 +3.16=63-------> 63g/moli
n= 126g : 63g/moli = 2 moli HNO3
28g CaO
MCaO= 40 + 16=56-----> 56g/moli
n= 28g : 56g/moli = 0,5 moli CaO
3.
m = n . M
2moli H2SO4
MH2SO4= 2+32 +4.16=98-------> 98g/moli
m = 2moli . 98g/moli = 196 g H2SO4
3,5moli Al2S3
M= 2.27 + 3.32= 150-------> 150g/moli
m= 3,5moli . 150g/moli = 525 g Al2S3
4.
3moli H3PO4
1 mol H3PO4 ----------6,023.10²³molecule H3PO4
3 moli----------------------------------------x
x= 3 . 6,023.10²³ = 18,069 .10²³molecule H3PO4
49 g H2SO4
MH2SO4=98----> 98g/moli
n= 49g : 98g/moli= 0,5 moli H2SO4
1 mol H2SO4----------6,023.10²³ molecule H2SO4
0,5 moli--------------------------y
y= 0,5 . 6,023.10²³ = 3,0115 . 10²³ molecule H2SO4
