Răspuns :
4H2CO3-----------8H-4C-12O----------Mh2co3 = 2x1 + 12 + 3x16 = 62 g/mol
5 CCl4-----------5C-20Cl-/---------------Mccl4 = 12 + 4x35,5 = 154 g/mol
4H2SO4------------8H-4S-16O----------Mh2so4 = 2x1 + 32 + 4x16 = 98 g/mol
6SO3-------------6S-18O-/-----------------Mso3 = 32 + 3x16 = 80 g/mol
Răspuns:
Explicație:
nr . molecule nr. atomi M
7NH3 N - 7 MNH3= 14 + 3 =17-------> 17g/moli
H - 21
3H2CO3 H - 6 MH2CO3= 2+ 12 + 3.16=62---> 62g/moli
C - 1
O - 9
5 C Cl4 C - 5 MC Cl4= 12 + 4 . 35,5=154---->154g/moli
Cl - 20
4H2SO4 H - 8 MH2SO4= 2+32 +4.16=98----> 98g/moli
S - 4
O - 16
6 SO3 S - 6 MSO3= 32 +3.16=80----> 80g/moli
O- 18