Răspuns :

Sebinsky2015id

1 mol HNO3........6,023*10^23 molecule HNO3.......63g HNO3

x..............................y...........................................................504g HNO3

x = 1*504/63 = 8 moli HNO3

y = 6,023*10^23*504/63 = 48,184*10^23 molecule HNO3

ID Alte intrebari