Răspuns :

[tex]11,2g........................................x\\Fe + CuSO4 => FeSO4 + Cu\\56g.........................................64g\\\\x=\frac{11,2*64}{56}=12,8g\\\\[/tex]

[tex]n=\frac{m}{M}=\frac{12,8}{64}=0,2 moli[/tex]