Răspuns:
Explicație:
MNaOH = 23 +16 +1=40-------> 40g/moli
n= 32 g : 40g/moli=0,8 moli NaOH
1mol NaOH------------6,023.10 ²³molecule
0,8 moli-------------------------x
x= 0,8 . 6,023.10²³molecule NaOH
MO2= 2.16=32--------> 32g/moli
MCaO= 40 +16=56-------> 56g/moli
MCa(NO3 )2= 40 + 2.14 + 6.16=164-------> 164g/moli
MHCl= 1 + 35, 5= 36,5-------> 36,5 g/moli
M AgNO3= 108 + 14 + 3.16=
M CuSO4= 64 + 32 + 4.16=
MNaOH= 23 +16 +1=40------>40g/moli
MAl2O3= 2,27 + 3.16=
MFe(OH )3= 56 + 3.16 +3=
MMg3 (PO4)2= 3. 24 + 2.31 + 8.16=
MHNO3= 1 + 14 + 3.16=63------> 63g/moli
MAl2 (SO4 )3= 2.27 + 3.32 + 12.16=342-------> 342g/moli
{am lasat cateva sa le calculezi }
