Răspuns:
M,MgO=40g/mol
M,o2=32g/mol
2x40g.......................32g
2MgO-------> 2Mg + O2
240g....................................x
x=m=96gO2
p=80%
p=m,px100/m,i---> m,p=80x150/100g=120g C pur
M,C=12g/mol
M,CO2=44g/mol
12g..............................44g
C + O2--------> CO2
120g.................................x
x=m=440gCO2 (10moli)
Explicație:
