Răspuns:
[tex]a)u^{-1}=(\frac{12}{10})^{-1}=\frac{10}{12}=\frac{5}{6}\\b)u*v=\frac{12}{10}*\frac{-1*3+1}{3}=\frac{12}{10}*\frac{-2}{3}=\frac{-8}{10}=\frac{-4}{5}\\c)\frac{u}{v}=\frac{\frac{12}{10}}{\frac{-2}{3}}=\frac{12}{10}*\frac{3}{-2}=\frac{36}{-20}=\frac{9}{-5}\\d)v^{3}=(\frac{-2}{3})^{3}=\frac{(-2)^{3}}{3^{3}}=\frac{-8}{27}[/tex]
