Răspuns:
a) → →
a(3,1) b(0,5)
→→
axb=(3,1)x(0,5)=3x0+1x5=5
b) → →
a(2,-4) b(6,2)
→→
axb=(2,-4)x(6,2)=2x6+(-4)x2=12-8=4
c) → →
a(rad2, 3) b(3rad2, 1)
→→
axb=(rad2, 3)x(3rad2, 1)= rad2x3rad2+3x1=6+1=7
d) → →
a(-8, 2/3) b(3/4, 9)
→→
axb=(-8, 2/3)x(3/4, 9)=(-8)x3/4+2/3x9=(-6)+6=0
Explicație pas cu pas:
