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A)ce volum de suc gastric (hcl 0.1m)se neutralizeaza cu o tableta ce contine 330 mg hidroxid de magneziu
b) ce volum de suc gastric (HCl 0.3%p=1g/ml)se neutralizeaza cu o tableta antiacida ce contine 500 mg carbonat de calciu

Răspuns :

Puia68id

Răspuns:

M,Mg(OH)2=68g/mol

M,HCl= 36,5g/mol

2X36,5g.......68g

2HCl +  Mg(OH)2---> MgCl2 + 2H2O

x...................0,330g

x=0,3542gHCl

niu,HCl= m/M= 0,3542/36,5mol=0,0097molHCl

c,m= niu/V----> V= 0,0097mol/0,1mol/l= 0,097 l= 97ml suc gastric

M,CaCO3=100g/mol

2x36,5gHCl.......100g

2HCl    +   CaCO3----> CaCl2 + 2H2O

x.....................0,5g

x=0,365gHCl=md

c=m ,dx100/ms---> ms= 0,365x100/0,3g=121,7gsolutie HCl(suc gastric)

v= ms/ro= 121,7g/1g/ml= 121,7ml suc gastric

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