Răspuns :
Răspuns a] 2HCl+ Mg[OH]2=MgCl2+2H2O M Mg[OH]2=24+2.16+2=58g/mol
Explicație: se transforma 330/1000=0,33g se calculeaza nr.moliHCl la 2moli HCl.............58g Mg[OH]2 XmoliHCl................0,33g X HCl=2.0,33/58=0,01moli HCl Concentatia molara Cm=Nr.moli/V V=Nr.moli/Cm=0,01/0,1=0,1L=100ml b] 500mg/1000=0,5g CaCO3+2HCl=CaCl2+H2O+CO2 MCaCO3=40+12 +3.16=100g/mol se calculeaza md HCl din reactie la 0,5gCaCO3............X gHCl 100gCaCO3................2.35,5g HCl X=mdHCl=0,365g HCl se aplica apoi C%=md.100/ms ms=md.100/C%=0,365.100/0,3=121,66g solutie HCl se aplica formula Ro=ms/V unde Ro= densitate se calculeaza V V=ms?Ro=121,66g/1g/ml=121,66mlHCl[suc gastric]