Răspuns:
3
.v= 3l=3000ml
ro=m/v--> m- roxv= 3000x1 g= 3000g
4.
ca sa calculezi c%. aplici relatia
c=mdx100/ms= mdx100/ ( md+ 3000) unde md este masa de NaCL dizolvata in apa
5
a..reactia dintre un acid si o baza este reactie de neutralizare
b.m=300gNaOH impur p= 80%
p= m,px100/m,i---> m,p= 300x80/100g= 240gNaOH pur
M,NaOH= 40g/mol
niu=m/M= 240/40mol=6molNaOH
1mol...........1mol........1mol
NaOH + HCl----> NaCl + H2O
6mol,......................x= niu=6molNaCl
c.
m,i= m,impur-m,pur=300-240=>60g
d
M,NaCl=58,5g/mol
niu=m/M= 50/58,5 mol=0,85molNaCl
e.
M,H2O=18g/mol
niu=m/M= 3/18mol=0,167mol H2O
Explicație:
