Răspuns:
CH3COOH
R.at. C:H: O=2:4:2
R.m. C:H:O=24:4:32=6:1:8
compozitie procentuala
MCH3COOH =2×24+4×1+2×16=60g/mol
60gCH3COOH .....24gC.....4gH......32gO
100gCH3COOH.......xgC......ygH.......zgO
x=100×24/60=calculează
y=100×4/60=calculează
z=100×32/60=calculează