Răspuns:
Explicație pas cu pas:
a) 2(x-4)-2(1-x)≤(3-√3)(3+√3), ⇒ 2x-8-2+2x≤3²-(√3)², ⇒ 4x-10≤9-3, ⇒4x≤6+10, ⇒ 4x≤16, ⇒ x≤4, Deci A={0,1,2,3,4}.
b) |x|<2(3-√(4·3))-2+√(16·3), ⇒ |x|<6-4√3-2+4√3, ⇒ |x|<4, x∈{-3,-2,-1,0,1,2,3}
Deci B={-3,-2,-1,0,1,2,3}.
A∩B={0,1,2,3,4}∩{-3,-2,-1,0,1,2,3}={0,1,2,3}
