Răspuns:
E(x) = [(x^2-4)/(x^2-9) -1]:[1/(x-3)+
1/(x+3)-1/(x^2-9)] x € R
x<>-3; x<>1/2; x<>3
"<>" =diferit
E(x)=[(x^2-4)/(x^2-9)- (x^2-9)/(x^2-9)]:
[(x+3)/(x-3)(x+3)+ (x-3)/(x-3)(x+3)-
1/(x-3)(x+3)]
E(x) = [(x-2)(x+2)- (x-3)(x+3)]/(x-3)(x+3) : [(x+3+x-3-1)/(x+3)(x-3)]
E(x)= [(x^2-4- x^2+9)/(x-3)(x+3)] ×
[(x+3)(x-3)/(2x-1)]
E(x) = 5/(x-3)(x+3)× (x-3)(x+3)/(2x-1)
E(x)= 5/ (2x-1)
x € R, x<>-3
x<> 3
x<> 1/2
Explicație pas cu pas:
