Răspuns:
a) (<AOB,<BOC,<COD,<DOA) D.P (7 , 5 , 8 , 4 )
[tex] \frac{ < aob}{7} = \frac{ < boc}{5} = \frac{ < cod}{8} = \frac{ < doa}{4} = k \\ \frac{ < aob}{7} = k = > \: < aob = 7k = 7 \times 15 = 105 \\ \frac{ < boc}{5} = k = > < boc = 5k = 5 \times 15 = 75 \\ \frac{ < cod}{8} = k = > < cod = 8k = 8 \times 15 = 120 \\ \frac{ < doa}{4} = k \: = > < doa = 4k = 4 \times 15 = 60\\ < aob + < boc + < cod + < doa = 360 = > 7k + 5k + 8k + 4k = 360 = > 24k = 360 = > k = \frac{360}{24} = > k = 15 \\ b)[/tex]
