Răspuns:
Explicație:
200g sol. Ca(OH)2
c=40%
r. cu NH4Cl
g , moli V de NH3
-se afla md sol. de Ca(OH)2
md= c . ms : 100
md= 200 . 40 : 100=80 g Ca(OH)2
80g xg
Ca(OH)2 + 2NH4Cl = CaCl2 + 2NH3 + 2H2O
74g 2.17g
x= 80. 34 : 74 =35,76 g NH3
n=35,76g : 17g/moli=2,103 moli NH3
VNH3= 2,103 moli . 22,4 L/moli=47,12 L
MNH3=14+3=17------> 17g/moli
MCa(OH)2=40 + 2.16 +2=74-------> 74g/moli
