Salut,
Conform figurii avem așa:
[tex]tg30^{\circ}=\dfrac{x}{4\sqrt3}\Leftrightarrow\dfrac{\sqrt3}3=\dfrac{x}{4\sqrt3}\Leftrightarrow \dfrac{1}{\sqrt 3}=\dfrac{x}{4\sqrt3}\Rightarrow x=4\ cm.[/tex]
Apoi:
[tex]sin30^{\circ}=\dfrac{x}y\Leftrightarrow\dfrac{1}2=\dfrac{4}y,\ deci\ y=8\ cm.[/tex]
Ai înțeles ?
Green eyes.
