Răspuns:
Explicație pas cu pas:
[tex]aa,a+bb,b+cc,c=\dfrac{aaa}{10}+\dfrac{bbb}{10}+\dfrac{ccc}{10}=\dfrac{100a+10a+a}{10}+\dfrac{100b+10b+b}{10}+\dfrac{100c+10c+c}{10}=\dfrac{111a}{10} +\dfrac{111b}{10}+\dfrac{111c}{10}=\dfrac{111a+111b+111c}{10}=\dfrac{111(a+b+c)}{10}=11,1(a+b+c).[/tex]