Buna!
a) H3C-CH2-CH2-CH2-CH3
FM=C5H12
RA: C:H=5:12
RM: C:H=5•12:12•1=5:1
Compoziția%
72total......60C.....12H
100..............xC.......yH
x=6000/72=83,33%C
y=1200/72=16,66%H
b)H2C=CH-CH2-CH3
FM=C4H8
RA: C:H=4:8=1:2
RM: C:H=4•12:8•1=48:8=6:1
Compoziția%
56.....48C.....8H
100.....xC.......yH
x=4800/56=85,714%C
y=800/56=14,285%H
La restul faci după același model
