Răspuns:
[tex] a = 4 {}^{n + 2} + 2 {}^{2n} - 2 {}^{2n + 3} = > (2 {}^{2} ) {}^{n + 2} + 2 {}^{2n} - 2 {}^{2n + 3} = > 2 {}^{2n + 4} + 2 {}^{n} - {2}^{2n + 3} = > 2 {}^{2n} ( {2}^{4} + {2}^{0} - {2}^{3} ) = > 2 {}^{2n} (16 + 1 - 8) = > 2 {}^{2n} \times 9 = > a = (2 {}^{2} ) {}^{n} \times (3 {}^{2}) = > a = (2 {}^{n} \times 3) {}^{2} [/tex]
