Salut,
[tex]\left(\dfrac{2}3\cdot x\sqrt x\right)^{'}=\left(\dfrac{2}3\cdot x^{1+1/2}\right)^{'}=\left(\dfrac{2}3\cdot x^{3/2}\right)^{'}=\dfrac{2}3\cdot\dfrac{3}2\cdot x^{3/2-1}=x^{1/2}=\sqrt x.[/tex]
Ai înțeles ?
Green eyes.
