Răspuns:
m(H2SO4)=40 g H2SO4+2NaOH=Na2SO4+2H2O
+NaOH v(H2SO4)=m/M=40g/98g/mol=0.4mol
v(NaOH)=? 0.4mol/1=v(NaOH)/2=>v(NaOH)=0.8mol
M(H2SO4)=98g/mol m(NaOH)=v*M=0.4*40=16g
M(NaOH)=40g/mol
Explicație:
1)Scriem ecuatia si o egalam
2)Aflam cantitatea de subst(v) de H2SO4 (masa(m)/masa molara(M))
3)facem un raport ((v)H2SO4/nr de molecule/v(NaOH)/nr de molecule)
4)Aflam v(NaOH)=(0.4mol*2)/1
5)m(NaOH)=v(NaOH)*M(NaOH)
