Răspuns:
Explicație:
Hristos a inviat!
Problema 10.101
ρ = ρ₀(1+∝×t)
ρ = R×S/l,
unde R-rezistenta, S-sectiunea conductorului, l-lungimea conductorului
ρ = ρ₀(1+∝×t), t=0°C⇒ρ = ρ₀
ρ₁=ρ₀(1+∝×t₁), t₁=3000°C⇒ρ₁=ρ₀(1+3000×48×10⁻⁴)=ρ₀(1+14,4)=15,5×ρ₀
ρ = R×S/l⇒ρ₀=R×S/l
ρ₁ = R₁×S/l⇒15,5×ρ₀=R₁×S/l
ρ₀/15,5×ρ₀=R/R₁⇒R/R₁=1/15,5
raspuns de 15,5 ori
Problema 10.102
ρ = ρ₀(1+∝×t)⇒ρ₀=ρ/(1+∝×t)
t=20°C⇒ρ₀=1,6×18⁻⁸/(1+4×10⁻³×20)=1,6×18⁻⁸/1,08=1,48×10⁻⁸Ω×m
t=600°C⇒ρ₀=1,48×10⁻⁸(1+4×10⁻³×600)=1,48×10⁻⁸×1,24=1,83×10⁻⁸Ω×m
