Răspuns :

Arimathid

Explicație pas cu pas:

Adevarat a inviat!

|2x-1|=1 si x∈Z ⇒ 2x-1= -1 sau 2x-1= 1

Daca 2x-1= -1|+1

2x=0⇒x=0

Daca 2x-1=1|+1

2x=2|:2

x=1

Asa ca x∈{0,1}

Rayzenid

|2x - 1| = 1

⇔ 2x - 1 = ±1

⇔ (2x - 1 = -1) ∨ (2x - 1 = 1)

⇔ (2x = -1 + 1) ∨ (2x = 1 + 1)

⇔ (2x = 0) ∨ (2x = 2)

⇔ (x = 0/2) ∨ (x = 2/2)

⇔ (x = 0) ∨ (x = 1)

⇒ x ∈ {0; 1}

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