Răspuns:
Explicație pas cu pas:
C1-C2=ip inΔAC1C2
C1C2=100√2≅141 m
C2C3-ip inΔC2BC3
C2C3²=120²+50²=14400+2500 C2C3=130m
C1-C2-C3=141+130=271 m
b) C1C²=100²+50²=10000+2500=12500 C1C≅111,8 m
C1-C-C3=111,8m+100=211,8 m<C1-C2-C3
C1-C-C3 este cea mai scurta distanta
