1/,
0,2 moli V L
C2H2 + 3/2O2 --> 2CO2 + H2O
1 1,5x22,4
=> V = 0,2x1,5x22,4/1 = 6,72 L O2
2/.
stim ca niu = masa/miu = V/V.molar
=> V = masaxV.molar/miu
miu.C4H10 = 58 g/mol, iar V.molar = 22,4 L in c.n.
=> V = 10x22,4/58 = 3,86 L
3/.
0,4 moli V L
CH3OH + 3/2O2 --> CO2 + 2H2O
1 22,4
=> V = 0,4x22,4/1 = 8,96 L CO2