Răspuns:
a)
2(x+1)= -7(x+3)+3(3x-5)-5
2x+2= - 7x-21+9x-15-5
2x+2= 2x-41
0x=-43
x=0
b)
-3(3x+1)+14=3(7x-3)-10
-9x-3+14=21x-9-10
-9x+11=21x-19
-9x-21x=-19-11
-30x= - 30 /:(-30)
x= 1
c)
14+2×[3-2(x-3)]:2=37
14+2×(3-2x+6):2=37
14+(6-4x+12):2=37
(6-4x+12):2=37-14
(6-4x+12):2=23
6-4x+12=46
6-4x=34
-4x=34-6
-4x=28 /:(-4)
x= -7
d) - 4-{6-[-3+(-3)+(-5-x)-7]-9}=1
-4-{6-[-3-3-5-x-7]-9}=1
-4-[6-(-18-x)-9]=1
-4-(6+18+x-9)=1
-4-(15+x)=1
-4-15-x=1
-19-x=1
-19-1=x
-20=x
x=-20
e)
5(7x-1)^0+2(x+1)= -7(x+3)+3(3x-5)+43
5+2x+2= -7x-21+9x-15+43
7+2x= 2x+7
0x=0
x=0
Explicație pas cu pas:
