Răspuns:
Explicație pas cu pas:
In Δ dreptunghic MQR
MR²=MQ²-QR²=20²-12²=8×32 MR=16 cm
T inaltimii QR²=RP×MR RP=144/16=9cm
MP=MR+RP=16+9=25 cm MP=MN
QP²=MP²-MQ² QP²=25²-20²=5×45 QP=15 cm=NQ
NP=2QP=30 cm
Pabc=2MP+NO=2×25+30=80 cm
Aabc=MQ×NP/2=20×30/2=300cm²