Răspuns:
2)
ms=500
md=100 ==>mH2O=ms-md=500-100=400 g
p(denistatea) H2O=1 g/cm3
p=m/V==> V=m/p ==> V=400g/1g/cm3 ==> V=400 cm3
5)
md=30
mH2O=160 ==> ms=mH2O+md=160+30=190 g
c=md*100/md ==> c=30*100/190 =15.789%
(calculezi volumul ca la 2, densitatea la apa fiind mereu 1g/cm3)
8)
ms=500
c=5% ==> c=md*100/ms ==> md=c*ms/100 ==> md=500*5/100 = 25g
md=25 ==> mH2O=ms-md=500-25=475g
(calculezi volumul ca la 2, densitatea la apa fiind mereu 1g/cm3)
10)
md=500
c=10% ==> c=md*100/ms ==> ms=100*md/c ==> ms=500*100/10=5000 g
ms=5000 g ==> mH2O=ms-md=5000-500=4500 g
(calculezi volumul ca la 2, densitatea la apa fiind mereu 1g/cm3)
11)
md=300
c=20% ==> c=md*100/ms ==> ms=100*md/c ==> ms=100*300/20=1500g
ms=1500g==> MH2O=ms-md=1500-300=1200g
(calculezi volumul ca la 2, densitatea la apa fiind mereu 1g/cm3)
