Răspuns:
6 pe 8 +(6pe 5-3 pe 10)=5 pe 4
[tex]\it \dfrac{\ 6^{(2}}{8}+\Big(\dfrac{^{2)}6}{\ 5}-\dfrac{3}{10}\Big)\cdot\dfrac{5}{9}=\dfrac{3}{4}+\dfrac{9}{10}\cdot\dfrac{5}{9}=\dfrac{3}{4}+\dfrac{^{2)}1}{\ 2} = \dfrac{5}{4}=1 \dfrac{1}{4}[/tex]
