1)
[tex]\it \Delta ABC-isoscel,\ AB=AC\\ \\ m(\hat B)=m(\hat C)=\dfrac{180^o-36^o}{2}=72^o\\ \\ m(\widehat{DBC}) =\dfrac{72^o}{2}=36^o\\ \\ \Delta ABC \sim\Delta BCD\ (cazul\ UU) \Rightarrow \dfrac{AB}{BC}=\dfrac{BC}{CD}\ \Rightarrow BC^2=AB\cdot CD[/tex]