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Pokju8888id

Răspuns:

Explicație:

K2CO3

M= 2 .39+ 12+3.16=138------>138g/moli

138g K2CO3-------------78g K---------12gC---------------48gO

100gK2CO3   -----------------x----------y---------------------z

x=100 . 78 : 138=56,52% K

y= 100.12: 138=8,7% C

z= 100.48 : 138=34,78 %O

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