Răspuns :
Răspuns:
la prima e facut dincolo
la ultima probabil e 2/4=1/2=1/1*2
Explicație pas cu pas:
vezi atasament
Al treilea:
[tex]\it 2s=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30} +\dfrac{1}{42}=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}=\\ \\ \\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}=1-\dfrac{1}{7}=\dfrac{6}{7}\\ \\ \\ Prin\ \ urmare\ \ 2s=\dfrac{6}{7} \Longrightarrow\ s=\dfrac{3}{7}[/tex]