problema 1
rezolvare :
Ab=πr²=π×4²=16π cm
conf.t. P. avem Δdr.
latura la patrat =3²+4²=16+9=25
latura=√25=5 cm
Al=Ab×latura=16π×5=80π cm²
At=Ab+Al=16π+80π=96π cm²
V=o treime×Ab×h=o treime×16π×3=16π cm la a treia
RASPUNS:
R=4
g=5
h=3
Ab=16π
Al=80π
At=96π
V=16π
problema 2
conf.t.P.avem Δdr.
h²=latura²-R²=13²-5²=169-25=144
h=√144=12 cm
Ab=πr²=π×5²=25π cm²
Al=Ab×g=25π×13=325π cm²
At=Ab+Al=325π+25π=350π cm²
V=o treime×Ab×h=o treime×25π×12=100π cm la a treia
RASPUNS:
R=5 g=13 h=12 Ab=25π Al=325π At=350π V=100π