1)n1 moli=0,25 NaOH
n2 moli=9 moli Apa
Calculăm masele dizolvate pt fiecare substanta
n1=m1/M=>m1=0,25*40=10 g NaOH
n2=m2/M=>m2=9*18=162 g H2O
ms=md+mH2O
ms=10+162
ms=172 g NaOH
C=md/ms*100
C=10/172*100
C=5,88%
2)md=C*ms/100
md=10*240/100
md=24 g NaCl
mH2O=ms-md
mH2O=240-24
mH2O=216 g
Baftă!
