1. Un oxiacid al sulfului are 2,040% H. Aflați formula sa chimică.
2. Se adaugă peste 200 g apă distilată 200 g soluție de acid sulfuric de c= 48%. Care va fi concentrația acidului după diluare?

Răspuns :

1/.

oxiacid al sulfului = HaSOn, a = valenta ionului SOn iar n = indicele at. O

100% ............................ 2,04% H

a+32+16n ................... a g H

=> 49a = a+32+16n

=> 48a = 32+16n

conditii

daca a = 1 => n = 1 => HSO => NU

        a = 2 => n = 4 => H2SO4 => DA

= acidul sulfuric

2/.

din c% => md = msxc%/100

=> 200x48/100 = 96 g

ms.final = ms + m.apa = 200+200 =400 g sol.

c%.final = mdx100/ms.final

= 96x100/400 = 24%

Răspuns:

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