Răspuns :
1/.
oxiacid al sulfului = HaSOn, a = valenta ionului SOn iar n = indicele at. O
100% ............................ 2,04% H
a+32+16n ................... a g H
=> 49a = a+32+16n
=> 48a = 32+16n
conditii
daca a = 1 => n = 1 => HSO => NU
a = 2 => n = 4 => H2SO4 => DA
= acidul sulfuric
2/.
din c% => md = msxc%/100
=> 200x48/100 = 96 g
ms.final = ms + m.apa = 200+200 =400 g sol.
c%.final = mdx100/ms.final
= 96x100/400 = 24%
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