Răspuns :

Albatranid

Răspuns:

Explicație pas cu pas:

76^63=(71+5)^63= M71+5^63

66^53=(71-5)^63=N71-5^53

insumand, obtinem M71+N71+5^53(5^10-1)=

P71+5^53( 5^5+1) (5^5-1)=P71+5^53(3125-1) (3125+1)= P71+5^53* 3126*3124, div cu 71 pt ca 3124=71*44

Obs

am nota M si N, P pt a arata ca sunt mutiplii iferiti

2k+1 nu vad ce importanta are aici

Targoviste44id

[tex]\it a=76^{63}+66^{53}=(71+5)^{63}+(71-5)^{53} =M_{71}+5^{63}+M_{71}-5^{53}=\\ \\ =M_{71}-5^{53}(5^{10}-1)\\ \\ 5^{10}-1=(5^5)^2-1=(5^5-1)(5^5+1) =3124\cdot3126=71\cdot44\cdot3126 =M_{71}\\ \\ \\ Deci,\ a=M_{71} -M_{71}=M_{71}[/tex]

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