125 kg. ........................ 100% impur
m ................................ 80% pur
= 100 kg benzen pur
100 kg md kg
C6H6 + HONO2 --H+--> C6H5-NO2 + H2O
78 63
=> md = 63x100/78 = 80,77 kg HNO3 consumat in reactie
100% .................... 80,77 kg consumat
105% ..................... n kg introduse
=84,80 kg HNO3 introduse
md = 84,80 kg, c% = 70% , c% = mdx100/ms
=> ms = mdx100/c% = 84,4x100/70
= 121,15 kg sol. HNO3