Răspuns:
Explicație:
msNaOH=200g
c=40%
CuSO4
produsii de reactie
-se afla md sol de NaOH
md= c.ms : 100
md=40. 200 : 100= 80g NaOH
80g xg yg
2 NaOH + CuSO4= Cu(OH)2 + Na2SO4
2.40g 98g 142g
x=80. 98 : 80=98g Cu(OH)2
n=98g : 98g/moli=1mol Cu(OH)2
Y=80.142 : 80=142g Na2SO4
n=142g : 142g/moli=1mol Na2SO4
MNaOH=23 +16 +1=40------->40g/moli
MCu(OH)2= 64 +2.16 +2=98----->98g/moli
MNa2SO4=2.23 = 32 +4.16=142------->142g/moli
