Răspuns:
c,m= niu/V
M,NaOH=40g/mol---> niu=160/40mol=4mol---> c.m= 4mol/16 l=>0,25M
se aplica relatia : niu=m/M---> m= niuxM
H2SO4 M=98g/mol niu= 600g/98g/mol=6,12mol
HCl M=36,5g/mol m= 2,5molx36,5g.mol=91,25g
Ca(OH)2 M=74g/mol m= 16molx74g/mol=1184g
Al2(SO4)3 M=342g/mol niu=425g/342g/mol=1,24mol
NaCl M= 58,5g/mol niu= 500g/58,5g/mol=8,55mol
VERIFICA, TE ROG, CALCULELEL !
Explicație: