Răspuns :

Se inmultesc mezii si extremii

3(x-2)=2(x+3)

3x-6=2x+6

Scadem 2x

x-6=6

Adunam 6

x=12

(x-2)/(x+3)=2/3 =>2(x+3)=3(x-2)

2x+6=3x-6

-x=12 * (-1)

x=-12