Răspuns:
[tex]\sqrt{6}[/tex]
Explicație pas cu pas:
[tex]M_{g}=>\sqrt{\frac{\sqrt{18}-\sqrt{2} }{\sqrt{12} -\sqrt{3} } *\frac{\sqrt{48}-\sqrt{3} }{\sqrt{18}-\sqrt{8} } } =\sqrt{\frac{3\sqrt{2} -\sqrt{2} }{2\sqrt{3}-\sqrt{3} }*\frac{4\sqrt{3}-\sqrt{3} }{3\sqrt{2}-2\sqrt{2} } } =\sqrt{\frac{2\sqrt{2} }{\sqrt{3} } *\frac{3\sqrt{3} }{\sqrt{2} } } =[/tex]
[tex]=\sqrt{\frac{2\sqrt{2}*3\sqrt{3} }{\sqrt{3}\sqrt{2} } } =\sqrt{\frac{2*3\sqrt{3} }{\sqrt{3} } } =\sqrt{2*3} =\sqrt{6}[/tex]
Succes! :)
