Răspuns:
Explicație:
MNaOH= ANa + AO +AH= 23 +16 +1
=40-------->40g/mol [ 40g NaOH------>1mol ]
MH2SO4=2 + 32 +4.16 =98---------> 98g/moli
MFe2O3= 2.56 + 3.16 =160--------> 160g/moli
MAgNO3= 108 +14 + 3.16 =170-------->170g/moli
MN2=2.14=28-------> 28g/moli
MO3=3.16=48------->48g/moli
MCuSO4=64 +32 +4.16=160--- - >160g/moli {pentru CuSO4 anhidru}
MCuSO4.5H2O= 160 + 5.18=160 + 90=250------> 250g/moli
